x^2-4x-184=0

Solution for x^2-4x-184=0 equation:

x^2-4x-184=0

a = 1; b = -4; c = -184;
Δ = b2-4ac
Δ = -42-4·1·(-184)
Δ = 752
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{752}=\sqrt{16*47}=\sqrt{16}*\sqrt{47}=4\sqrt{47}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4\sqrt{47}}{2*1}=\frac{4-4\sqrt{47}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4\sqrt{47}}{2*1}=\frac{4+4\sqrt{47}}{2}
$